24x^2+71x+35=0

Solution for 24x^2+71x+35=0 equation:

24x^2+71x+35=0

a = 24; b = 71; c = +35;
Δ = b2-4ac
Δ = 712-4·24·35
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-41}{2*24}=\frac{-112}{48}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+41}{2*24}=\frac{-30}{48}
=-5/8
$